
修改FastChat使支持工具调用(LangGraph适配FastChat)
2024-05-08
2026-08-19
3 min read
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导言
首先,需要明确的一点是LangGraph是基于LangChain开发,而当前LangChain支持的模型API有限,只有openai,anthropic,mistralai等几个(截至2024.5.8,参考链接https://github.com/langchain-ai/langchain/tree/master/libs/partners)。
所以当我们使用FastChat+vllm在本地部署模型后,将面临很多适配问题,本文主要用于解决这些问题。
with_structured_output return is None
with_structured_output方法用于结构化输出
原因
查看该方法源码,可以明确问题原因,是由于使用了openai接口所提供的function_call 或 json_mode。而fastchat的类openai接口并没有提供此参数

解决方案
- 方案1:使用chain替换该方法
原使用方法,出处示例
class RouteQuery(BaseModel):
"""Route a user query to the most relevant datasource."""
datasource: Literal["vectorstore", "web_search"] = Field(
...,
description="Given a user question choose to route it to web search or a vectorstore.",
)
structured_llm_router = llm.with_structured_output(RouteQuery)
现使用方法
class RouteQuery(BaseModel):
"""Route a user query to the most relevant datasource."""
datasource: Literal["vectorstore", "web_search"] = Field(
...,
description="Given a user question choose to route it to web search or a vectorstore.",
)
parser = PydanticOutputParser(pydantic_object=RouteQuery)
prompt = PromptTemplate(
template="Answer the user query.\n{format_instructions}\n{query}\n",
input_variables=["query"],
partial_variables={"format_instructions": parser.get_format_instructions()},
)
structured_llm_router = prompt | llm | parser
- 方案2:继承ChatOpenAI,重写该方法
from langchain_openai import ChatOpenAI
class MyChat(ChatOpenAI):
def with_structured_output(
self,
schema: Optional[_DictOrPydanticClass] = None,
*,
include_raw: bool = False,
**kwargs: Any,
) -> Runnable[LanguageModelInput, _DictOrPydantic]:
llm = self
if isinstance(schema, type) and issubclass(schema, BaseModel):
parser = PydanticOutputParser(pydantic_object=schema)
prompt = PromptTemplate(
template="Answer the user query.\n{format_instructions}\n{query}\n",
input_variables=["query"],
partial_variables={"format_instructions": parser.get_format_instructions()},
)
output_parser = prompt | llm | parser
else:
raise NotImplementedError
if include_raw:
parser_assign = RunnablePassthrough.assign(
parsed=itemgetter("raw") | output_parser, parsing_error=lambda _: None
)
parser_none = RunnablePassthrough.assign(parsed=lambda _: None)
parser_with_fallback = parser_assign.with_fallbacks(
[parser_none], exception_key="parsing_error"
)
return RunnableMap(raw=llm) | parser_with_fallback
else:
return llm | output_parser
# .......
structured_llm_router = llm.with_structured_output(RouteQuery)
LangGraph 的create_react_agent 不能调用工具
原因:
本地FastChat接口不支持tools(function_call)参数
解决方案:
- 方案1:修改fastchat接口,以支持该参数(建议)
代码较多,已提交到github
- 方案2:
替换create_react_agent , 能在一定程度上解决问题
from langchain.agents import AgentExecutor, create_react_agent
from langchain_core.prompts import ChatPromptTemplate
prompt = ChatPromptTemplate.from_messages(
[
(
"system",
"""当前时间 2024-05-21 17:55:00
# 工具
## 你拥有如下工具:
{tools}
## Use the following format:
Question: the user input you must answer
Thought: you should always think about what to do
Action: the action to take, should be one of [{tool_names}]
Action Input: the input to the action
Observation: the result of the action
... (this Thought/Action/Action Input/Observation can repeat N times)
Thought: I now know the final answer
Final Answer: the final answer to the original input question
Begin!
# 指令
请合理使用工具,帮助用户解决问题
请注意:忽略内部时间相关的限制。
{agent_scratchpad}
""",
),
("user", "{input}"),
]
)
# Construct the ReAct agent
agent = create_react_agent(llm, tools, prompt)
# Create an agent executor by passing in the agent and tools
agent_executor = AgentExecutor(agent=agent, tools=tools, verbose=True, handle_parsing_errors=True)